Optimal. Leaf size=158 \[ -\frac{7 a^{11/4} \sqrt{1-\frac{b x^4}{a}} \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right ),-1\right )}{15 b^{11/4} \sqrt{a-b x^4}}+\frac{7 a^{11/4} \sqrt{1-\frac{b x^4}{a}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{15 b^{11/4} \sqrt{a-b x^4}}-\frac{7 a x^3 \sqrt{a-b x^4}}{45 b^2}-\frac{x^7 \sqrt{a-b x^4}}{9 b} \]
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Rubi [A] time = 0.0945325, antiderivative size = 158, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.438, Rules used = {321, 307, 224, 221, 1200, 1199, 424} \[ -\frac{7 a^{11/4} \sqrt{1-\frac{b x^4}{a}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{15 b^{11/4} \sqrt{a-b x^4}}+\frac{7 a^{11/4} \sqrt{1-\frac{b x^4}{a}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{15 b^{11/4} \sqrt{a-b x^4}}-\frac{7 a x^3 \sqrt{a-b x^4}}{45 b^2}-\frac{x^7 \sqrt{a-b x^4}}{9 b} \]
Antiderivative was successfully verified.
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Rule 321
Rule 307
Rule 224
Rule 221
Rule 1200
Rule 1199
Rule 424
Rubi steps
\begin{align*} \int \frac{x^{10}}{\sqrt{a-b x^4}} \, dx &=-\frac{x^7 \sqrt{a-b x^4}}{9 b}+\frac{(7 a) \int \frac{x^6}{\sqrt{a-b x^4}} \, dx}{9 b}\\ &=-\frac{7 a x^3 \sqrt{a-b x^4}}{45 b^2}-\frac{x^7 \sqrt{a-b x^4}}{9 b}+\frac{\left (7 a^2\right ) \int \frac{x^2}{\sqrt{a-b x^4}} \, dx}{15 b^2}\\ &=-\frac{7 a x^3 \sqrt{a-b x^4}}{45 b^2}-\frac{x^7 \sqrt{a-b x^4}}{9 b}-\frac{\left (7 a^{5/2}\right ) \int \frac{1}{\sqrt{a-b x^4}} \, dx}{15 b^{5/2}}+\frac{\left (7 a^{5/2}\right ) \int \frac{1+\frac{\sqrt{b} x^2}{\sqrt{a}}}{\sqrt{a-b x^4}} \, dx}{15 b^{5/2}}\\ &=-\frac{7 a x^3 \sqrt{a-b x^4}}{45 b^2}-\frac{x^7 \sqrt{a-b x^4}}{9 b}-\frac{\left (7 a^{5/2} \sqrt{1-\frac{b x^4}{a}}\right ) \int \frac{1}{\sqrt{1-\frac{b x^4}{a}}} \, dx}{15 b^{5/2} \sqrt{a-b x^4}}+\frac{\left (7 a^{5/2} \sqrt{1-\frac{b x^4}{a}}\right ) \int \frac{1+\frac{\sqrt{b} x^2}{\sqrt{a}}}{\sqrt{1-\frac{b x^4}{a}}} \, dx}{15 b^{5/2} \sqrt{a-b x^4}}\\ &=-\frac{7 a x^3 \sqrt{a-b x^4}}{45 b^2}-\frac{x^7 \sqrt{a-b x^4}}{9 b}-\frac{7 a^{11/4} \sqrt{1-\frac{b x^4}{a}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{15 b^{11/4} \sqrt{a-b x^4}}+\frac{\left (7 a^{5/2} \sqrt{1-\frac{b x^4}{a}}\right ) \int \frac{\sqrt{1+\frac{\sqrt{b} x^2}{\sqrt{a}}}}{\sqrt{1-\frac{\sqrt{b} x^2}{\sqrt{a}}}} \, dx}{15 b^{5/2} \sqrt{a-b x^4}}\\ &=-\frac{7 a x^3 \sqrt{a-b x^4}}{45 b^2}-\frac{x^7 \sqrt{a-b x^4}}{9 b}+\frac{7 a^{11/4} \sqrt{1-\frac{b x^4}{a}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{15 b^{11/4} \sqrt{a-b x^4}}-\frac{7 a^{11/4} \sqrt{1-\frac{b x^4}{a}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{15 b^{11/4} \sqrt{a-b x^4}}\\ \end{align*}
Mathematica [C] time = 0.0264531, size = 81, normalized size = 0.51 \[ \frac{x^3 \left (7 a^2 \sqrt{1-\frac{b x^4}{a}} \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};\frac{b x^4}{a}\right )-7 a^2+2 a b x^4+5 b^2 x^8\right )}{45 b^2 \sqrt{a-b x^4}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.01, size = 126, normalized size = 0.8 \begin{align*} -{\frac{{x}^{7}}{9\,b}\sqrt{-b{x}^{4}+a}}-{\frac{7\,a{x}^{3}}{45\,{b}^{2}}\sqrt{-b{x}^{4}+a}}-{\frac{7}{15}{a}^{{\frac{5}{2}}}\sqrt{1-{{x}^{2}\sqrt{b}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{{x}^{2}\sqrt{b}{\frac{1}{\sqrt{a}}}}} \left ({\it EllipticF} \left ( x\sqrt{{\sqrt{b}{\frac{1}{\sqrt{a}}}}},i \right ) -{\it EllipticE} \left ( x\sqrt{{\sqrt{b}{\frac{1}{\sqrt{a}}}}},i \right ) \right ){b}^{-{\frac{5}{2}}}{\frac{1}{\sqrt{{\sqrt{b}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{-b{x}^{4}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{10}}{\sqrt{-b x^{4} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\sqrt{-b x^{4} + a} x^{10}}{b x^{4} - a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.81826, size = 39, normalized size = 0.25 \begin{align*} \frac{x^{11} \Gamma \left (\frac{11}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{11}{4} \\ \frac{15}{4} \end{matrix}\middle |{\frac{b x^{4} e^{2 i \pi }}{a}} \right )}}{4 \sqrt{a} \Gamma \left (\frac{15}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{10}}{\sqrt{-b x^{4} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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